Let $x, y \in [0, \infty)$ each be an D4767: Unsigned real number such that

(i)	\begin{equation} x < y \end{equation}

Then \begin{equation} \sqrt{x} < \sqrt{y} \end{equation}

Let $x, y \in [0, \infty)$ each be an D4767: Unsigned real number.

Then \begin{equation} x < y \quad \implies \quad \sqrt{x} < \sqrt{y} \end{equation}