Let $P = (\{ 1, 2, 3, 4 \}, \mathcal{F}, \mathbb{P})$ be a D6122: Standard uniform discrete probability space.

Then

(1)	$\{ 1, 2 \}, \{ 1, 3 \}, \{ 2, 3 \}$ is a D2148: Pairwise independent event collection
(2)	\begin{equation} \mathbb{P}(\{ 1, 2 \} \cap \{ 1, 3 \} \cap \{ 2, 3 \}) = \mathbb{P} (\emptyset) = 0 \neq \frac{1}{2^3} = \mathbb{P} \{ 1, 2 \} \mathbb{P} \{ 1, 3 \} \mathbb{P} \{ 2, 3 \} \end{equation}