Let $n, m \in \mathbb{N}$ each be a D996: Natural number such that
(i) | \begin{equation} 1 \leq m \leq n \end{equation} |
Then
\begin{equation}
\frac{n + 1}{m + 1} \binom{n}{m}
= \binom{n + 1}{m + 1}
\end{equation}