Let $n, m \in \mathbb{N}$ each be a D996: Natural number such that

(i)	\begin{equation} 1 \leq m \leq n \end{equation}

Then \begin{equation} \frac{n + 1}{m + 1} \binom{n}{m} = \binom{n + 1}{m + 1} \end{equation}