Let $X$ be a D11: Set such that
| (i) | $E \subseteq X$ is a D78: Subset of $X$ |
| (ii) | $X \setminus E$ is the D79: Set complement of $E$ within $X$ |
Then
\begin{equation}
E \cap (X \setminus E)
= \emptyset
\end{equation}
